新聞中心
背景

創(chuàng)新互聯(lián)建站專(zhuān)注為客戶(hù)提供全方位的互聯(lián)網(wǎng)綜合服務(wù),包含不限于網(wǎng)站制作、網(wǎng)站建設(shè)、南江網(wǎng)絡(luò)推廣、微信小程序開(kāi)發(fā)、南江網(wǎng)絡(luò)營(yíng)銷(xiāo)、南江企業(yè)策劃、南江品牌公關(guān)、搜索引擎seo、人物專(zhuān)訪(fǎng)、企業(yè)宣傳片、企業(yè)代運(yùn)營(yíng)等,從售前售中售后,我們都將竭誠(chéng)為您服務(wù),您的肯定,是我們最大的嘉獎(jiǎng);創(chuàng)新互聯(lián)建站為所有大學(xué)生創(chuàng)業(yè)者提供南江建站搭建服務(wù),24小時(shí)服務(wù)熱線(xiàn):18982081108,官方網(wǎng)址:www.cdcxhl.com
老實(shí)說(shuō),C++11中對(duì)異步的支持不必Python和JavaScript弱。
實(shí)現(xiàn)(代碼)
- #include
- #include
- #include
- #include
- template
- int parallel_sum(RAIter front, RAIter beg, RAIter end)
- {
- auto len = end - beg;
- if (len < 1000)
- {
- char out[50];
- sprintf(out, "Calculate from %d to %d\n", beg - front, end - front);
- std::cout << out;
- return std::accumulate(beg, end, 0);
- }
- RAIter mid = beg + len / 2;
- auto handle_right = std::async(std::launch::async,
- parallel_sum
, front, mid, end); - auto handle_left = std::async(std::launch::async,
- parallel_sum
, front, beg, mid); - return handle_left.get() + handle_right.get();
- }
- int main()
- {
- std::vector
v(20000, 1); - std::cout << "The sum is " << parallel_sum(v.begin(), v.begin(), v.end()) << '\n';
- }
輸出
可能一
- Calculate from 8125 to 8750
- Calculate from 18125 to 18750
- Calculate from 10625 to 11250
- Calculate from 2500 to 3125
- Calculate from 13750 to 14375
- Calculate from 5000 to 5625
- Calculate from 1250 to 1875
- Calculate from 3750 to 4375
- Calculate from 16250 to 16875
- Calculate from 17500 to 18125
- Calculate from 10000 to 10625
- Calculate from 625 to 1250
- Calculate from 18750 to 19375
- Calculate from 15625 to 16250
- Calculate from 3125 to 3750
- Calculate from 12500 to 13125
- The sum is 20000
可能二
- Calculate from 1875 to 2500
- Calculate from 3750 to 4375
- Calculate from 8750 to 9375
- Calculate from 7500 to 8125
- Calculate from 15000 to 15625
- Calculate from 10000 to 10625
- Calculate from 1250 to 1875
- Calculate from 6875 to 7500
- Calculate from 0 to 625
- Calculate from 3125 to 3750
- Calculate from 5625 to 6250
- Calculate from 5000 to 5625
- Calculate from 6250 to 6875
- Calculate from 2500 to 3125
- The sum is 20000
可能.........
注意
如果在輸出中間信息的時(shí)候不先現(xiàn)在字符串里輸出會(huì)很亂,因?yàn)橥恍衏out輸出不同項(xiàng)的操作不是原子的,中間可能會(huì)轉(zhuǎn)到其他線(xiàn)程去。
文章標(biāo)題:[ModernC++]現(xiàn)代C++中的異步操作
鏈接地址:http://fisionsoft.com.cn/article/dpjoipd.html


咨詢(xún)
建站咨詢(xún)
